4x^2=9/64

Solution for 4x^2=9/64 equation:

4x^2=9/64

We move all terms to the left:

4x^2-(9/64)=0

We add all the numbers together, and all the variables

4x^2-(+9/64)=0

We get rid of parentheses

4x^2-9/64=0

We multiply all the terms by the denominator


4x^2*64-9=0

Wy multiply elements

256x^2-9=0

a = 256; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·256·(-9)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-96}{2*256}=\frac{-96}{512}
=-3/16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+96}{2*256}=\frac{96}{512}
=3/16
$